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15y^2-54y+27=0
a = 15; b = -54; c = +27;
Δ = b2-4ac
Δ = -542-4·15·27
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1296}=36$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-54)-36}{2*15}=\frac{18}{30} =3/5 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-54)+36}{2*15}=\frac{90}{30} =3 $
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